Sub vs. Cruiser

2 subs attacking 1 cruiser. Do the subs automatically win? Or, how does the combat work.

Not automatic.
Both subs get to roll an attack. If one hits, its over. If they both miss (better than 50% chance they miss), the attacker has to decide whether they want to stay and keep attacking. If they stay, cruiser gets to shoot back once before sub or subs get to attack again.

Not automatic.
Both subs get to roll an attack. If one hits, its over. If they both miss (better than 50% chance they miss), the attacker has to decide whether they want to stay and keep attacking. If they stay, cruiser gets to shoot back once before sub or subs get to attack again.
Almost. If the subs miss then the cruiser gets a shot back. After that then the attacker decides whether or not to keep attacking. The same sequence happens again in the second round if they decide to push the attack. The sequence continues until the cruiser or the subs are destroyed, or the subs submerge.

Not automatic.
Both subs get to roll an attack.� If one hits, its over.� If they both miss (better than 50% chance they miss), the attacker has to decide whether they want to stay and keep attacking.� If they stay, cruiser gets to shoot back once before sub or subs get to attack again.
No, chances that they both miss are 2/3 x 2/3 = 4/9, so there’s a better than 50% chance that they hit. Also, if they both miss, the cruiser always shoots back that round, before the subs can decide whether to stay for the next round.

@Herr:
Not automatic.
Both subs get to roll an attack.ï¿½ If one hits, its over.ï¿½ If they both miss (better than 50% chance they miss), the attacker has to decide whether they want to stay and keep attacking.ï¿½ If they stay, cruiser gets to shoot back once before sub or subs get to attack again.
No, chances that they both miss are 2/3 x 2/3 = 4/9, so there’s a better than 50% chance that they hit. Also, if they both miss, the cruiser always shoots back that round, before the subs can decide whether to stay for the next round.
4 / 9 = .44

here’s a coulpe links: http://www.edcollins.com/backgammon/diceprob.htm
http://www.geteasysolution.com/24iswhatpercentof36
So according to this you have a 66.6% chance of rolling a 1 or a 2 when throwing 2, 6 sided dice. I find it somewhat confusing, but it seems to make sense. : )
Kinda cool that he uses a Axis and Allies reference too
Well that guy is wrong or more likely I misinterpreted his info. Here’s how redrum explains 2 subs attacking 1 cruiser:
“So one thing to remember is the battle calc is approximate and just averages based on the run count (increasing run count should get closer to the true value). That said the chance with dice that 2 subs get at least 1 hit in the first round is ~55.56%. The easiest way to think about it is what is the chance of both subs missing? The answer is (4/6) * (4/6) = 4/9 = 44.44% so the chance that 1 or both hit is 100%  44.44% = 55.56%. So the battle calc is pretty close given you only have it set to 400 run count.”
Guess i should have read Herr Kaleun’s post a little closer

It’s also worth remembering that one sub on one cruiser is a coin flip, because the cruiser only rolls its attack if the sub misses.
Final word?