here’s a coulpe links: http://www.edcollins.com/backgammon/diceprob.htm
http://www.geteasysolution.com/24-is-what-percent-of-36
So according to this you have a 66.6% chance of rolling a 1 or a 2 when throwing 2, 6 sided dice. I find it somewhat confusing, but it seems to make sense. : )
Kinda cool that he uses a Axis and Allies reference too :)
Well that guy is wrong or more likely I misinterpreted his info. Here’s how redrum explains 2 subs attacking 1 cruiser:
“So one thing to remember is the battle calc is approximate and just averages based on the run count (increasing run count should get closer to the true value). That said the chance with dice that 2 subs get at least 1 hit in the first round is ~55.56%. The easiest way to think about it is what is the chance of both subs missing? The answer is (4/6) * (4/6) = 4/9 = 44.44% so the chance that 1 or both hit is 100% - 44.44% = 55.56%. So the battle calc is pretty close given you only have it set to 400 run count.”
Guess i should have read Herr Kaleun’s post a little closer :)