[Global 1940] New turn order

@general-5-stars said in [Global 1940] Funny How...:

We play Uk 1 inf or art can use the hump from Assam to Yunnan if China controls Yunnan.

You could have roll a 1 and it blocks the piece based on lost planes.

Or a 2 blocks it like all limits said. Think using a bomber plane is to much. Just lose the 6 icps.

Come on. Test test test.

@The-Captain

Thanks for the advice!

@Ichabod:

@simon33:

Strikes me that the factory downgrade when you lose and regain a major is harsh and arguably unfair.

What if factories are limited to the production value of the territory if not on original soil, but also limited by the type of factory? .

Do you mean this restriction (of producing only the value number of the territory) only to apply for the countries that capture the major, like Japan capturing India, or the US landing on W. Germany just to reduce the factory to a minor?

I would think this would be another way to add some balance. Forward factories next to Russia only producing 2 units for Germany…ect.

Yeah, that’s what I’m saying.

Hi Erocco,
these numbers are based on a formula found during Classic time by Dauvio Vann and his friends, then improved and adjusted to better fit the need of Second Edition units. Here is one link in House Rule:
http://www.axisandallies.org/forums/index.php?topic=40346.msg1684954#msg1684954

Below, you get the whole formula and a short explanation:

@Baron:

@Dauvio:

It came to my attention that one of my formulas are already out there that I discovered 30 years ago.
http://www.axisandallies.org/forums/index.php?action=profile;u=185969 has also discovered the formula P^2*N=S
And just for fun you can try these formulas also. S/P^2=N. √(S/N)=P
P=POINTS
N=NUMBER OF UNITS
S=STRENGTH OF ONE KIND OF UNITS IN A TERRITORY
This formula should replace the punch formula. It is much better then the punch formula.

Now the next formula is (P100)/(C^26)=S
P=POINTS
C=COST
S=STRENGTH OF THE UNIT BASED ON COST
With this formula you can also price units according to their strength. √((P100)/(S6))=C
This formula is for points. (S*(C^2*6))/100=P

For better results for some of these formulas, have all your units cost ten times then what they are. These are some of the VANN FORMULAS I came up 30 years ago.

If you have any questions about these formulas, please ask.

I found how you can get the main part of Vann formula or Baron-Larrymarx according to a specific unit as benchmark.

I took the Fighter A3 D4 C10 and I wanted to convert into Tank A3 D3 C6 as benchmark (Baron-Larrymarx formula).

Then I saw what I did.

Power (of attacking Fighter): A3 * C6 (cost of Tank)/C10 (cost of Fg) * 1 Hit Point C6 (cost of Tank)/C10 (cost of Fg) = 1.08
You can reduce this equation because (cost of Tank)(cost of Tank)/ (cost of Fg)*(cost of Fg) is same to
(cost of Tank) IPCs^2 / (cost of Fg) IPCs^2 and give a simple ratio.

C6^2*A3/C10^2 = 1.08
36 squared IPCs 3 Power * 1 Hit /100 squared IPCs = 1.08 PowerHit Point

This explained what is hidden in Baron-Larrymarx formula:
Offence or defence strength factor= 36*Power/Cost^2.

The whole Enigma formula is
Refence unit Cost^2Power of the actual unit1 HP/Cost of the actual unit^2

So, the Basic offence or defence strength factor result (1.08, in this case) is express in Power*Hit Point
1^2*Power (of a given unit)*1 hit/Cost (of this same given unit)^2

And this formula can be adapt according to any benchmark, for instance a 1 IPC unit:
131 hit/10^2 = 0.300

And this is a very small number. That’s why Vann formula:
Strength= (Power100)/(Cost^26)

add an arbitrary 1001/6= 16.667…
So, 16.667131 hit/10^2 = 0.5
And this would provide the Fighter strength attack factor based on an hypothetical benchmark unit of √16.667 = 4.0825 IPCs.
A 5 IPCs revised Tank in Vann formula gives a Strength : 16.66731 hit/5^2 = 2.00 powerhit

Can you elaborate on the ship calculations?

Destroyer strength: .30144/8^2  = 0.675
Cruiser    strength: .60144/12^2= 0.600
Battleship strength: .701442.618/20^2 = 0.660

These numbers means that Destroyer is the most optimized unit for combat to buy for each IPC invested, then it is battleship and finally Cruiser.
Said otherwise, Cruiser is sub-optimal for the cost.
3 DDs C8 A3 D3 (A9 D9, 3 hits) will be stronger than 2 Cruisers C12 A6 D6 (A12 D12, 2 hits) if you can use a Battlecalc to test D10-sided values.

From stronger to weaker for 120 IPCs basis:
15 DDs A3 D3 (A45 D45)
6 BBs A7 D7 (A42 D42)
10 CAs A6 D6 (A60 D60)

As much as I enjoy playing pacific 40 on tripleA, I still prefer playing it on the board game.  I enjoy seeing huge navies clash in the pacific with lots of chips. :)

Here is an example of the failure of bombing a small coastal emplacement at Normandy:

"SAINT-MARCOUF : THE CRISBECQ BATTERY
GERMAN COASTAL DEFENSE

The only heavy battery on the eastern coast of the Cotentin Peninsula, the Crisbecq Battery, was located 2.5 kilometers from the shore on a crest overlooking all of Utah Beach. From Crisbecq, the Germans could see and defend the entire coastline from Saint-Vaast-la-Hougue to Grandcamp.

Although it was never completed, the Crisbecq battery was the keystone of this portion of the German Atlantic Wall with three, long-range 210 mm cannons and a garrison of 400 men. The Allies dropped over 800 bombs on Crisbecq between April 19 and June 6, 1944. This unrelenting aerial attack climaxed on the night of June 5 when 101 four-engine bombers unleashed 598 tons of explosives on the battery. On June 6, the surroundings were unrecognizable, but the guns were still intact.

At 6 am on D-Day, as GI’s were landing on Utah Beach, Crisbecq opened fire, sinking an American destroyer.

The battery held out for several days, despite shelling by U.S. battleships and attacks from the American Infantry in hand-to-hand trench combat.

To repel the Allied assault, the German commander of Crisbecq radioed to the Azeville battery and requested that it fire on his position. Crisbecq was finally taken at 8:20 am on June 12, after the German commandment ordered its troops to evacuate to La Pernelle, between Quettehou and Barfleur. The fierce German resistance momentarily halted the Allied Advance to the north. "

Just pulled that off of a google search on D-Day.  I’m not trying to be a chump with this post, just noting that “bunkers” were built to be hidden (maybe not all of them) and to withstand such an attack even if discovered before ground operations.  I mean if 101 heavy bombers in one mission the night before D-Day have little impact why should a SBR inflict damage on a bunker?

How did you edit the map?

Yeah, that’s pretty much what it is.